how many grams of kno3 should be used to prepare
2.00 l of a 0.500m solution
To calculate the grams of KNO3 required to prepare a 0.500 M solution in a 2.00 L volume, you would need to use the formula:
grams = (Molarity x Volume x Molar Mass) / 1000
Here's how to calculate it step by step:
Step 1: Determine the molar mass of KNO3.
K (potassium) = 39.10 g/mol
N (nitrogen) = 14.01 g/mol
O (oxygen) = 16.00 g/mol
Molar mass (KNO3) = (39.10 g/mol) + (14.01 g/mol x 1) + (16.00 g/mol x 3)
= 101.11 g/mol
Step 2: Substitute the given values into the formula.
Molarity = 0.500 M (moles per liter)
Volume = 2.00 L
Molar Mass = 101.11 g/mol
Note: We divide by 1000 to convert from grams to kilograms.
grams = (0.500 mol/L x 2.00 L x 101.11 g/mol) / 1000
= 50.555 g
Therefore, approximately 50.555 grams of KNO3 should be used to prepare a 2.00 L volume of a 0.500 M KNO3 solution.