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physics

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The following forces act on a hockey puck (round, rubber disk) sitting on a frictionless surface: F_1 = 12 N at 15 degrees; F_2 = 28 N at 125 degrees; and F_3 = 33.3 N at 235 degrees. All the forces are in the plane of the ice. Determine the net force on the puck.

  • physics -

    Net force= sum of all.

    First, net force at 0 degrees
    F@0=12cos15+28cos125+33.3cos235
    calculate those, and add.
    Then, the forces at 90 deg
    F@90=12sin15+28sin125+33.3sin235
    calculate, and sum.

    Net force= sum of those two forces.
    I like to do it this way.
    1) angle=arctan F@0/F@90
    2) magnitude= F@0/cos(angle)

    check that logic.

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