At noon a private plane left Austin for Los Angeles, 2100 km away, flying at 500km/h. One hour later a jet left Los Angeles for Austin at 700 km/h. At what time did they pass each other?

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The fly a combined 2100km

2100km=500km/hr*time1 + 700km/hr*time2
but time2=time1-1

2100=500*time1+700(time1-1)
now solve for time 1

The equation to simply put words into numbers would be....."500x + 700x - 700 = 2100".....

Then if you solved for "x", you would get x=7/3.
So the plane and jet will meet in 7/3 hours. If yoy add that to 12:00 PM being noon, you would get 2:20, so the plane and the jet will meet at 2:20 PM.

To find out when the two planes pass each other, we need to determine the time it takes for each plane to reach the point of intersection. Let's break down the problem step by step:

1. The private plane leaves Austin and starts flying towards Los Angeles at a speed of 500 km/h.
2. The second plane, a jet, leaves Los Angeles one hour later and starts flying towards Austin at a speed of 700 km/h.
3. In one hour, the private plane has already covered a distance of 500 km (500 km/h × 1 h = 500 km).
4. The remaining distance between Austin and Los Angeles is 2100 km - 500 km = 1600 km.
5. Now, both planes are heading towards each other. The combined speed of the two planes is 500 km/h + 700 km/h = 1200 km/h.
6. To find the time it takes for the two planes to meet, we can divide the remaining distance (1600 km) by their combined speed (1200 km/h).
Time = Distance / Speed = 1600 km / 1200 km/h = 1.33 hours.

Therefore, the two planes will pass each other 1.33 hours after the private plane left Austin.

To determine the exact time, we need to add this time to the departure time of the private plane.

Since the private plane left at noon, we can convert the remaining time (0.33 hours) to minutes.

0.33 hours × 60 minutes/hour ≈ 19.8 minutes

So, they will pass each other approximately 19.8 minutes after 1:00 PM.

Therefore, the two planes will pass each other at around 1:19.8 PM.