Physics
posted by ana .
What is the gas pressure inside the box shown in the figure?
I have a picture but website wouldn't allow me to post the link for the picture.
So I am trying my best to describe it.
it is a ushape tube and it is holding mercury in it. One side has 16cm of mercury and other side has 6cm.
what i did was p_gas:
101300+(9.81*13600*.16*.06)..doesn't work

There should be mercury in both sides of the tube, with a higher column height on the side opposite to the side with the gas.
The gas pressure equals
P= (mercury density) g h,
where h is the difference in the mecruty column heights.
You do not have to add 101300 (atmosheric pressure) to get the absolute pressure with a utube manometer such as this.
P = 9.81 m/s^2*13600 kg/m^3*(.16.06) m 
i got 13341.6 ...it is incorrect

i figured it out..thanks for helping me

Annie, how can you say that...it is my question i am still working on it

sorry Ana... i missed typed it...again i apologize

difference between height is 10 cm so use 0.1 instead of 0.6 and you should get 88000