# pre algebra

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solve equation.. i continually keep getting this problem wrong

x/3=x/5-2

• pre algebra -

Since 5-2=3, saying x/3=x/3 isn't really saying anything. Multiply each side by 3/1 if you don't believe me. Did you copy it down correctly?

• pre algebra -

ok so for this you do
x/3=x/5-2

you multiple both sides by 3
so you have

x=x/15 -6
then go on from there

• pre algebra -

Brit's math is incorrect.

In contrast to Averageman, I am assuming that your equation is really:

x/3 = x/5 - 2

Not x/3 = x/(5-2)

Multiply both sides by 15 to get rid of both denominators.

5x = 3x - 30

Subtract 3x from both sides.

2x = -30

Divide both sides by 2.

x = -15

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