pre algebra
posted by jerson .
solve equation.. i continually keep getting this problem wrong
x/3=x/52

Since 52=3, saying x/3=x/3 isn't really saying anything. Multiply each side by 3/1 if you don't believe me. Did you copy it down correctly?

ok so for this you do
x/3=x/52
you multiple both sides by 3
so you have
x=x/15 6
then go on from there 
Brit's math is incorrect.
In contrast to Averageman, I am assuming that your equation is really:
x/3 = x/5  2
Not x/3 = x/(52)
Multiply both sides by 15 to get rid of both denominators.
5x = 3x  30
Subtract 3x from both sides.
2x = 30
Divide both sides by 2.
x = 15
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