Math

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Determine an equation of the circle that is tangent to both axes, has its center in the fourth quadrant and passes through the point (8, -9).

Help please?

Thanks much!

  • Math -

    well, you know if it is tangent to both axis, the center is at r,-r

    It passes through 8,-9 so the distance from that point to the center is also r.

    r^2=(8-r)^2 + (-9+r)^2
    = 64-16r+r^2+81-18r+r^2
    r^2-34r-145=0

    (r-29)(r-5)=0
    r=29, or r=5

    check both answers.
    then put it in standard form.

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