If an engine must do 500 joules of work to pull a 100 N load up to a height of 4 meters, What is the efficiency of the engine?
eff=workout/workin = 4*100/500 * 100=80percent
The force of gravtitation between two objects is 500 Newtons. What would the force of gravitation be if the distance between these to objects increased by 10 times?
10kg*9.81m/s^2=98.1N*4m=392.4J
392.4J/500=78.48% efficiency
To calculate the efficiency of an engine, we need to use the formula: Efficiency = useful work output / total energy input. In this case, the useful work output is the work done by the engine to pull the load, which is 500 joules. The total energy input is the product of the force (100 N) and the distance (4 meters), which is equal to 400 joules.
Now, we can calculate the efficiency of the engine using the formula:
Efficiency = (useful work output / total energy input) * 100%
Efficiency = (500 joules / 400 joules) * 100%
Efficiency = 1.25 * 100%
Efficiency = 125%
Therefore, the efficiency of the engine is 125%.