Perform Operations with Complex Number:
Solve the equation.
x^2+121=0
This is not about trigonometry.
x^2 = -121
x = the square root of -121.
x^2 = -121
x = ± 11i
sorry, i just wanted a check for my solutions of these two questions:
x^2+9=14
Solution:�}�ã5
2x^2+18=-72
Solution:�}3i�ã5
sorry. the solutions dont't come up the way I posted it.
But for first question:
x= + and - square root of 5
For the second question:
x= + and - 3i square root of 5
To solve the equation x^2 + 121 = 0, we need to make use of the properties of complex numbers.
Step 1: Rewrite the equation in standard form
x^2 + 121 = 0
Step 2: Subtract 121 from both sides of the equation
x^2 = -121
Step 3: Take the square root of both sides
√(x^2) = ±√(-121)
Step 4: Simplify the square root of -121, considering it as the square root of -1 times the square root of 121
√(x^2) = ±√(-1) * √(121)
Step 5: Simplify the square root of -1 as "i" (the imaginary unit) and the square root of 121 as 11
x = ±11i
Hence, the solutions to the equation x^2 + 121 = 0 are x = 11i and x = -11i.