Algebra
posted by Murajabash .
Did I do this right?
Find the vertex, the x intercepts and y intercepts.
f(x)=(x2)^24
Vertex: 2,4
X intercepts: 0,0 4,0
Y intercepts: I didn't know how to get these. Could you explain?

Isn't the vertex at 0,4?
y intercepts are when x is zero
y=2^24 or 0
x intercepts are when y is zero
0=(x2)^2 4
x2=+2
x=0, 4
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