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Assuming the mass of 5% Acetic Acid is 1.0g/mL, what volume of acetic acid is required to neutralize 25.0mL of 0.10M NaOH?

  • Chemistry -

    You have to convert the acid to moles.

    .05*1g/ml*volumeacid /molmassAceticAcid=25ml*.1

    volumeacid= 2.5ml/.05 * molmassAceticAcid

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