# sigma notation

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find the value of the sum

n sigma i=1 (2-5i)

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find the indicated sum not sure how to type the sigma sign, but here is the problem 6 on top of the sigma sign. under the sigma sign is i=3 and on the right side of the sigma sign (3i-2)
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Express the sum using summation notation: 1 - 1/2 + 1/3 - 1/4 + 1/5 - ... (to 3n terms) If I'm doing this right so far, with k=1 (the number on bottom of the sigma), the equation after the sigma would be ((-1)^(k+1)) / k I'd be able …
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Express the sum using summation notation: 1 - 1/2 + 1/3 - 1/4 + 1/5 - ... (to 3n terms) If I'm doing this right so far, with k=1 (the number on bottom of the sigma), the equation after the sigma would be ((-1)^(k+1)) / k I'd be able …
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Express the sum using summation notation: 1 - 1/2 + 1/3 - 1/4 + 1/5 - ... (to 3n terms) If I'm doing this right so far, with k=1 (the number on bottom of the sigma), the equation after the sigma would be ((-1)^(k+1)) / k I'd be able …
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hi i startted the problem below by writing a sigma notation of sigma[(2^(n+1))/((n+1)!)] QUESTION: how do i find the sum of 2+(4/2!)+(8/3!)+(16/4!)+... was my attempt wrong, or how do i go from here?
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hi i startted the problem below by writing a sigma notation of sigma[(2^(n+1))/((n+1)!)] QUESTION: how do i find the sum of 2+(4/2!)+(8/3!)+(16/4!)+... was my attempt wrong, or how do i go from here?