A minor league baseball team plays 117 games in a season. If the team won 17 more than three times as many games as they lost how many wins and loses did the team have
Let W = number of games won
Let L = number of games lost
L + W = 117, Then W = 117-L
3L + 17 = W
Substitute 117-L for W in the second equation and solve for L. Put that value of L in the first equation to find W. Put both values in the second equation to check your answers.
To solve this problem, we can set up a system of equations based on the given information.
Let's assume the number of games the team lost is "x."
According to the given information, the team won "17 more than three times as many games as they lost." So, the number of games the team won can be represented as "3x + 17."
Now, we can set up an equation based on the total number of games played in a season.
The total number of games played is the sum of wins and losses, which is 117:
x + (3x + 17) = 117
Simplifying the equation, we get:
4x + 17 = 117
Subtracting 17 from both sides:
4x = 100
Dividing both sides by 4:
x = 25
Now that we know x is 25, we can substitute this value back into the equation to find the number of wins:
3x + 17 = 3(25) + 17 = 75 + 17 = 92
Therefore, the team had 92 wins and 25 losses in the season.