A midweseren music competition awarde 34 ribbons. The number of blue ribons awarded was 2 less than the number of white ribbons. THe number of red ribons was 3 more than the number of white ribbons. How many of eah kind of ribbon awarded
Use the method described in you following post to solve this question.
To find the number of each kind of ribbon awarded, let's use algebraic equations.
Let's represent the number of white ribbons as "W".
According to the given information, the number of blue ribbons is 2 less than the number of white ribbons, which can be written as "W - 2".
The number of red ribbons is 3 more than the number of white ribbons, which can be written as "W + 3".
We also know that the total number of ribbons awarded is 34. Therefore, we can write the equation:
W + (W - 2) + (W + 3) = 34
Simplifying the equation, we get:
3W + 1 = 34
Subtracting 1 from both sides, we obtain:
3W = 33
Now, divide both sides of the equation by 3:
W = 11
So, there were 11 white ribbons awarded.
To find the number of blue ribbons:
W - 2 = 11 - 2 = 9
Therefore, there were 9 blue ribbons awarded.
To find the number of red ribbons:
W + 3 = 11 + 3 = 14
Hence, there were 14 red ribbons awarded.
In conclusion, there were 11 white ribbons, 9 blue ribbons, and 14 red ribbons awarded in the competition.