At work one day, Erica Franz received 36 packages. Speedy Delivery delivered three times as many as Ralph's Express delivered four more than send quick package service . how many packgeds did each service deliver to Erica
6.666
Let's solve the problem step-by-step.
Let's say the number of packages delivered by Send Quick Package Service is x.
According to the problem, Ralph's Express delivered four more than Send Quick Package Service. So, Ralph's Express delivered x + 4 packages.
And Speedy Delivery delivered three times as many packages as Ralph's Express. So, Speedy Delivery delivered 3 * (x + 4) packages.
The total number of packages received by Erica is 36.
Therefore, we can write the equation:
x + x + 4 + 3 * (x + 4) = 36
Now, let's solve for x:
x + x + 4 + 3x + 12 = 36
5x + 16 = 36
5x = 20
x = 4
So, Send Quick Package Service delivered 4 packages, Ralph's Express delivered 4 + 4 = 8 packages, and Speedy Delivery delivered 3 * (4 + 4) = 24 packages.
Therefore, Send Quick Package Service delivered 4 packages, Ralph's Express delivered 8 packages, and Speedy Delivery delivered 24 packages to Erica.
To determine how many packages each delivery service delivered to Erica, we can use algebraic equations. Let's call the number of packages delivered by Speedy Delivery as "S", the number of packages delivered by Ralph's Express as "R", and the number of packages delivered by Send Quick Package Service as "Q".
According to the problem, we are given three pieces of information:
1) Speedy Delivery delivered three times as many packages as Ralph's Express:
S = 3R
2) Ralph's Express delivered four more packages than Send Quick Package Service:
R = Q + 4
3) Erica received a total of 36 packages:
S + R + Q = 36
Now we can solve these equations to find the values of S, R, and Q.
Substituting the value of S from the first equation into the third equation:
3R + R + Q = 36
4R + Q = 36
Substituting the value of R from the second equation into the third equation:
4(Q + 4) + Q = 36
4Q + 16 + Q = 36
5Q + 16 = 36
5Q = 36 - 16
5Q = 20
Q = 20 / 5
Q = 4
Substituting the found value of Q back into the second equation:
R = Q + 4
R = 4 + 4
R = 8
Substituting the found values of R and Q into the first equation:
S = 3R
S = 3 * 8
S = 24
Therefore, Speedy Delivery delivered 24 packages, Ralph's Express delivered 8 packages, and Send Quick Package Service delivered 4 packages to Erica.
SD=3RE
RE=SQPS+4
SD+RE+RE+SQPS=36
3RE +RE+RE+RE-4=36
go from there.