Physics
posted by Anonymous .
A tennis ball of mass m = 0.065 kg and speed v = 25 m/s strikes a wall at a 45° angle and rebounds with the same speed at 45° (Fig. 729). What is the impulse given the wall?
I started out with finding the momentum and doubling it to get the impulse on the wall but that isn't the right answer. What equation do I need to start this one? Does it have to do with the angles they are giving me?

No, that is not right. Only the normal component doubles.
Vfinalnormal =25*.707*2
Force*time=m*vfinalnormal
You have to only dealt with what changed, the momentum normal, and the implulse norma.
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