Algebra

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(4x^3-9x+8x^2-18)/(x+2)-use synthetic division to divide. I set it up like this (pretend the parentheses are the synthetic division box).

(-2)
4 8 -27

4 0 -27.


For remainders, according to my book, we're supposed to divide the remainder by the divisor. So it would be -27/-2. Yet my book says there is no remainder. It says the answer is 4x^2-9. How did it get this?

  • Algebra -

    Well Jeremiah, it's as simple as your forgetting the -9x term

    try
    (-2)
    4 8 -9 -18

    I get 4 0 -9 0

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