CaSO4.2H2O ==> CaSO4 + 2H2O
moles CaSO4.2H2O = 15.00 g x (1 mole CaSO4.2H2O/172.172) = 0.08712 moles.
moles CaSO4 = same.
grams CaSO4 = moles CaSO4 x molar mass CaSO4 = ??
Wait,.. how do I know the moles CaSO4?
do I do .08712* CaSO4's gfm?
sorry i'm a bit confused, what are we trying to find?
I recognize this from my post last night. Since you have 0.08712 mole of CaSO4.2H2O AND there is 1 mole CaSO4 per 1 mole CaSO4.2H2O (from the equation), then you must have 0.08712 mole CaSO4.
Then moles CaSO4 x molar mass CaSO4 = grams CaSO4. It's approximately 12 grams.
To find the moles of CaSO4 in the reaction CaSO4.2H2O ⟶ CaSO4 + 2H2O, you can consider the stoichiometry of the reaction. The stoichiometry tells you the ratio in which the reactants and products are combined.
In this case, the stoichiometry states that 1 mole of CaSO4.2H2O produces 1 mole of CaSO4. Therefore, if you have 0.08712 moles of CaSO4.2H2O, you will also have 0.08712 moles of CaSO4.
To find the grams of CaSO4, you can use the molar mass of CaSO4. The molar mass of CaSO4 is calculated by adding up the atomic masses of each element in the compound:
Ca = 40.08 g/mol, S = 32.06 g/mol, O = 16.00 g/mol (multiply by 4 because there are four oxygen atoms)
Molar mass of CaSO4 = (40.08 g/mol) + (32.06 g/mol) + (16.00 g/mol x 4) = 136.14 g/mol
Now, you can calculate the grams of CaSO4:
grams CaSO4 = moles CaSO4 x molar mass CaSO4
grams CaSO4 = 0.08712 moles x 136.14 g/mol = 11.86 grams.
To determine the moles of CaSO4 in the given reaction, you can use stoichiometry. Since the coefficient of CaSO4 is 1 in the balanced equation, the number of moles of CaSO4 will be the same as the moles of CaSO4.2H2O.
So, in this case, the moles of CaSO4 will also be 0.08712 moles.
To calculate the grams of CaSO4, you can use the molar mass of CaSO4, which is 136.14 g/mol. Multiply the moles of CaSO4 by its molar mass:
grams CaSO4 = moles CaSO4 x molar mass CaSO4
= 0.08712 moles x 136.14 g/mol
= 11.87 grams CaSO4