an extremely volatile substance, Ofnetite, has a half-life of 25 minutes. Find the percentage decrease of this substance in the first two hours.
To find the percentage decrease of the substance, Ofnetite, in the first two hours, we'll use the concept of half-life.
First, let's determine the number of half-lives that occur in two hours. Since the half-life of Ofnetite is 25 minutes, we need to convert two hours to minutes:
2 hours = 2 * 60 = 120 minutes.
Next, we divide the total time (120 minutes) by the half-life (25 minutes) to find the number of half-lives:
120 minutes / 25 minutes = 4.8 half-lives.
Since we cannot have a fraction of a half-life, we round down to the nearest whole number. Therefore, there are four half-lives within the first two hours.
Now, we can calculate the percentage decrease per half-life. For each half-life, the substance decreases by half (50%). Thus, the percentage decrease per half-life is 50%.
To find the total percentage decrease within the first two hours, we multiply the percentage decrease per half-life (50%) by the number of half-lives (4):
50% * 4 = 200%.
Therefore, the percentage decrease of the substance Ofnetite in the first two hours is 200%. This means that after two hours, the substance will be reduced to 0%.