# trig

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How do I find the "exact value" for the arcsin of -pi/3 radians?

• trig -

I hope you mean sine of -PI/3. ARCsin makes no sense, because you already have the angle.

PI radians is 180 deg, so PI/3 must be 60 deg. Now notice it is negative (300deg).

I assume you long ago memorized the 30-60-90 triangle functions.

• trig -

That's weird, my paper clearly says arcsin of -pi/3 radians. So should I just say this isn't possible..or would -pi/3 still be the answer? or would i write -(sqrt 3)/2?

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