posted by Anonymous .
How do I find the "exact value" for the arcsin of -pi/3 radians?
I hope you mean sine of -PI/3. ARCsin makes no sense, because you already have the angle.
PI radians is 180 deg, so PI/3 must be 60 deg. Now notice it is negative (300deg).
I assume you long ago memorized the 30-60-90 triangle functions.
That's weird, my paper clearly says arcsin of -pi/3 radians. So should I just say this isn't possible..or would -pi/3 still be the answer? or would i write -(sqrt 3)/2?