BLIND BATS AT HALLOWEEN
There were number of bats in a cave.
Two bats can see out of right eye,
Three bats can see out of left eye, Four can't see out of left eye, and
Five can't see out of right eye.
What is the least number of bats in the cave & what might their eyesight have been?
(Totally Blind- Blind Right Eye-etc.
7 bats
To determine the least number of bats in the cave and their eyesight, let's analyze the given information:
1. Two bats can see out of the right eye.
2. Three bats can see out of the left eye.
3. Four bats can't see out of the left eye.
4. Five bats can't see out of the right eye.
Let's break it down step by step:
Step 1: Start with the bats that can see out of both eyes (neither eye is blind).
- Since we know that four bats can't see out of the left eye and five bats can't see out of the right eye, there are four bats with a blind left eye and five bats with a blind right eye.
- Therefore, there must be at least five bats with neither eye blind.
Step 2: Add bats with a blind left eye.
- Since four bats can't see out of the left eye, we already have four bats in this category.
Step 3: Add bats with a blind right eye.
- Since five bats can't see out of the right eye, we already have five bats in this category.
Step 4: Add bats with both eyes blind.
- We have already determined that there are two bats that can see out of the right eye and three bats that can see out of the left eye.
- Since each bat with both eyes blind would contribute to the count of bats with a blind left eye and a blind right eye, we need to find the minimum number of bats that can fit this criterion.
- There must be at least two bats that have both eyes blind.
Step 5: Sum up the bats from each category.
- We have five bats with neither eye blind.
- We have four bats with a blind left eye.
- We have five bats with a blind right eye.
- We have two bats with both eyes blind.
So, the least number of bats in the cave is:
5 + 4 + 5 + 2 = 16
And the breakdown of their eyesight is:
- Five bats have neither eye blind.
- Four bats have a blind left eye.
- Five bats have a blind right eye.
- Two bats have both eyes blind.
Therefore, there are 16 bats in the cave, with their eyesight categorized as mentioned above.
To solve this riddle, we need to determine the least number of bats in the cave and their eyesight conditions.
Let's analyze the information provided:
- Two bats can see out of their right eye.
- Three bats can see out of their left eye.
- Four bats can't see out of their left eye.
- Five bats can't see out of their right eye.
First, let's start with the bats that can't see out of their right eye. Since five bats can't see out of their right eye, these five bats must be part of the group that can't see out of the right eye.
Next, let's consider the bats that can see out of their right eye. Since there are two bats that fall into this category, we can include these two bats in our count.
After that, we can move on to the bats with sight in their left eye. It is mentioned that three bats can see out of their left eye, so we include these three bats as well.
Lastly, four bats can't see out of their left eye. Since we have already included two bats (with sight in the right eye) and three bats (with sight in the left eye), we now have a total of five bats in our count. Therefore, the remaining four bats that can't see out of their left eye must be the same four bats that can't see out of their right eye.
To summarize, based on the information given, we have:
- Two bats that can see out of their right eye.
- Three bats that can see out of their left eye.
- Four bats that can't see out of their left eye.
- Five bats that can't see out of their right eye.
The minimum number of bats in the cave is therefore five. Their potential eyesight conditions are as follows:
- Two bats are totally blind.
- Three bats can see out of their left eye only.
- Four bats can't see out of their left eye.
- Five bats can't see out of their right eye.
Only seven bats are described (4 + 3) and (5 + 2) for the condition of each eye.
Assuming that no bats can see out of both eyes, let's designate right eye see as RS, and not see as RN, doing similar notation with the left eye.
RS LN
RS LN
RN LS
RN LS
RN LS
RN LN
RN LN
Translate that into your answers.