Math
posted by Anonymous .
Find the variance for the given data. Round your answer to one more decimal place than the original data.
{8.5, 4.5, 8.8, 6.9, 5.3}

First find the mean. Then find the difference of each score from the mean. (As a check, the sum of these differences should be zero.) Square each difference and find their sum. Divide that sum by n (number of scores) to get your variance.
I'll let you do the work.
I hope this helps. Thanks for asking. 
I wouldn't want you to do the work, so thank you!
Mean is 6.8
6.88.5=1.7^2=2.89
6.84.5=2.3^2=5.29
6.88.8=2^2=4
6.86.9=0.1^2=0.1
6.85.3=1.5^2=2.25
14.53/5=2.906
1.705 
Is my work correct? I think I messed up somewhere in the process.

And I wanted to ask is it standard for the sums to always add up to 0? Thank you for that tip.

Doesn't .1 * .1 =.01?
However, I did not check the whole process. 
The sum of the differences from the mean will always add to zero, assuming that you have not made a mistake.
Remember that the mean acts as a balance point for the distribution, so the scores on one side (+) must equal the scores on the other (). 
Mean is 6.8
6.88.5=1.7^2=2.89
6.84.5=2.3^2=5.29
6.88.8=2^2=4
6.86.9=0.1^2=0.01
6.85.3=1.5^2=2.25
14.44/5=2.888 So the variance is 2.9!!
1.6994
Wow! Thanks for catching that, it changed the entire process. I appreciate your help.