Could some please tell me if I did these problems correctly? (I know that I did not Cancel common aqueous ions yet)

Question

Could some please tell me if I did these problems correctly? (I know that I did not Cancel common aqueous ions yet)

Question:
Write the net ionic equation for the following
1)Mixing solution of barium acetate and sodium phosphate
2)Mixing solution of thallium sulphate and magnesium chloride

My answer:
1)
3Ba2+(aq)+6CH3COO –(aq)+6Na+(aq)+2PO43-(aq)=Ba3 (PO4)2(s)+6CH3COO –(aq)+2Na3+ (aq)

2)
2Ti+(aq)+SO42–(aq)+Mg2+(aq)+2Cl–(aq) =2TiCl (s)+SO4-2(aq)+Mg-2(aq)

Thank you

Answer 1

I thought thallium sulfate is soluble. Check that.

Answer 2

I thought I put it as soluble, because I broke it up to 2Ti+(aq)and SO42–(aq. Correct me if I'm wrong. Is the rest okay?

Answer 3

You have a real problem with thallium. You are using Ti and that's titanium. See Tl here.

http://www.webelements.com/thallium/

Answer 4

To determine if you have correctly written the net ionic equations, we need to check if the compounds are balanced and if the charges are properly canceled.

1) Mixing solution of barium acetate and sodium phosphate:
The balanced chemical equation for the reaction between barium acetate (Ba(CH3COO)2) and sodium phosphate (Na3PO4) is:
3 Ba(CH3COO)2(aq) + 2 Na3PO4(aq) → Ba3(PO4)2(s) + 6 CH3COONa(aq)

To write the net ionic equation, we need to identify the spectator ions (ions that are present on both sides of the equation and do not participate in the reaction). In this case, the sodium ions (Na+) and acetate ions (CH3COO–) are spectator ions, so they can be omitted from the net ionic equation.

The net ionic equation becomes:
3 Ba2+(aq) + 2 PO43–(aq) → Ba3(PO4)2(s)

Your answer:
3 Ba2+(aq) + 6 CH3COO–(aq) + 6 Na+(aq) + 2 PO43–(aq) → Ba3(PO4)2(s) + 6 CH3COO–(aq) + 2 Na3+(aq)

You did not cancel the spectator ions (Na+ and CH3COO–). The correct net ionic equation is:
3 Ba2+(aq) + 2 PO43–(aq) → Ba3(PO4)2(s)

2) Mixing solution of thallium sulphate and magnesium chloride:
The balanced chemical equation for the reaction between thallium sulfate (Tl2SO4) and magnesium chloride (MgCl2) is:
2 Tl2SO4(aq) + 3 MgCl2(aq) → 2 TlCl(s) + 3 MgSO4(aq)

To write the net ionic equation, we need to identify the spectator ions. In this case, both magnesium ions (Mg2+) and sulfate ions (SO42–) are spectator ions.

The net ionic equation becomes:
2 Tl2+(aq) + 3 Cl–(aq) → 2 TlCl(s)

Your answer:
2 Ti+(aq) + SO42–(aq) + Mg2+(aq) + 2 Cl–(aq) → 2 TiCl(s) + SO42–(aq) + Mg2+(aq)

You did not cancel the spectator ions (SO42– and Mg2+). The correct net ionic equation is:
2 Ti2+(aq) + 3 Cl–(aq) → 2 TiCl(s)

In conclusion, you did not correctly write the net ionic equations. Remember to cancel out the spectator ions present on both sides of the equation to obtain the net ionic equation.