# Math

posted by
**Salman**
.

Use linear approximation, i.e. the tangent line, to approximate 1.6^3 as follows:

Let f(x) = x ^3. The equation of the tangent line to f(x) at x = 2 can be written as y=12x-16

Using this, we find our approximation for 1.6 ^3 is ???????