if 500 g of KCLO3 decomposes and produces 303 g of KCL, how many grams of O2 are produced?

Hmmmm.

500-303=?

If 500 g of KClO3 decomposes and produces 303g of KCl, how many grams of 02 are produced?

2KClO3→2KCl + 3O2

To determine the amount of grams of O2 produced, we can use the law of conservation of mass. According to this law, the total mass of the reactants before a chemical reaction is equal to the total mass of the products after the reaction.

First, we need to find the mass of KCLO3 that decomposed by subtracting the mass of KCL produced from the initial mass of KCLO3:

Mass of KCLO3 decomposed = Initial mass of KCLO3 - Mass of KCL produced
Mass of KCLO3 decomposed = 500 g - 303 g
Mass of KCLO3 decomposed = 197 g

Since the decomposition of KCLO3 only produces KCL and O2, we can assume that the mass of O2 produced is equal to the mass of KCLO3 decomposed. Therefore, the mass of O2 produced is 197 g.

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The answer is 21 g