Which solution contains 0,1 mol of sodium hydroxide?

A- 1 cm3 of 0,1 mol dm3 NaOH
B 10 cm3 of 0,1 mol dm3 NaOH
C 100 cm3###################
d 100 cm3 ###################

Moles= Molarity*volume in dm^3

So what do we have to do in this case?

Your question asks for 0.1 mole. So I would multiply molarity x volume in dm^3 and see which equals 0.1 mole. By the way, the answer choices aren't very clear; for example, 0.1 mole dm^3 is what? Does that mean 0.1 mole/dm^3 or does it have another meaning?

Well, if you're looking for a solution that contains 0.1 mol of sodium hydroxide, I wouldn't recommend option C or D. They seem to be lacking some important information there, most likely some digits. As for option A, 1 cm3 might not be enough to hold 0.1 mol of NaOH. So, by process of elimination, I'm going to go with option B, 10 cm3 of 0.1 mol dm3 NaOH. It seems like the safest bet, my friend.

To identify the solution that contains 0.1 mol of sodium hydroxide, we need to calculate the amount of NaOH in each solution.

The equation to calculate the amount of a substance is:
Amount (mol) = Concentration (mol/dm3) × Volume (dm3)

Let's calculate the amount of NaOH in each option:

A - 1 cm3 of 0.1 mol/dm3 NaOH:
Amount = 0.1 mol/dm3 × 0.001 dm3 = 0.0001 mol

B - 10 cm3 of 0.1 mol/dm3 NaOH:
Amount = 0.1 mol/dm3 × 0.01 dm3 = 0.001 mol

C - 100 cm3 of 0.1 mol/dm3 NaOH:
Amount = 0.1 mol/dm3 × 0.1 dm3 = 0.01 mol

D - 100 cm3 of 0.1 mol/dm3 NaOH:
Amount = 0.1 mol/dm3 × 0.1 dm3 = 0.01 mol

From the calculations, we can see that both options C and D contain 0.01 mol of sodium hydroxide, which is equal to 0.1 mol/dm3.