A hammer thrower releases the hammer after reaching an angular velocity of 14.9 rad/s. If the hammer is 1.6m from the shoulder joint, what is the linear velocity at release?
To find the linear velocity at release, we need to relate the angular velocity to the linear velocity using the formula:
Linear velocity = Radius × Angular velocity
Given:
Angular velocity (ω) = 14.9 rad/s
Radius (r) = 1.6 m
Substituting the values into the formula:
Linear velocity = 1.6 m × 14.9 rad/s
Calculating the result:
Linear velocity = 23.84 m/s
Therefore, the linear velocity at release is 23.84 m/s.