algebra
posted by Brett .
how do i factor 8m^26mn9n^2

If you had
8x^2  6x  9 can you see how I factored it to
(4x+3)(2x3) ? 
8x^2  6x  9
For this problem we have to multiply the first and the last term here the first term is 8 and the last term is 9 if we multiplied this two we will get 72 then we have to split this number in to two parts and the multiplication value of splitted term must be equal to 72 and the simplification value must be equal to the midlle term that is 6 .So we can split 72 as (12)*6
8x^26x9 = (2x3)(4x+3)
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