Rusty the elephant was thirsty, despite the fact that water made up 85% of his body weight. After drinking a considerable amount of water, Rusty weighed 1350 pounds, and water made up 86% of his body weight.

What was Rusty's weight before he had his drink? What was the weight of the water he drank?

To solve this problem, we can set up a system of equations based on the information given.

Let's assume Rusty's weight before he had his drink is x pounds. We can express this as:

Weight of Rusty = x pounds

According to the problem, water makes up 85% of Rusty's body weight. We can calculate the weight of water in pounds as:

Weight of water in pounds = 0.85x

After drinking water, Rusty's weight becomes 1350 pounds, and water makes up 86% of his body weight. We can express this information as:

Weight of Rusty + Weight of water = 1350 pounds ----(1)
Weight of water = 0.86 * (Weight of Rusty) ----(2)

Now, we can substitute the value of the weight of water from equation (2) into equation (1) to solve for Rusty's weight before he had his drink.

x + 0.86x = 1350

Combining like terms:

1.86x = 1350

Dividing both sides by 1.86:

x = 1350 / 1.86

Calculating this gives us:

x ≈ 725.81 pounds

Therefore, Rusty's weight before he had his drink was approximately 725.81 pounds.

To find the weight of the water he drank, we can subtract Rusty's weight after drinking water from Rusty's initial weight.

Weight of water he drank = Rusty's weight before drink - Rusty's weight after drink

Weight of water he drank = 725.81 pounds - 1350 pounds

Calculating this gives us:

Weight of water he drank ≈ -624.19 pounds

However, this result is negative, which doesn't make sense in the context of the problem. It suggests that the given information may not be consistent or there may be an error. Please double-check the problem statement or any additional information provided to ensure accuracy.