calculus  antiderivative
posted by thomas .
can someone help me find the antiderivative of:
f'(x) = (x^21)/x where f(1)=1/2, and f(1) = 0
Thanks!

f'(x) = x  1/x
Integrate one term at a time.
f(x) = x^2/2  ln x + C
If f(1) = 1/2, then C = 0
(for x>0 only)
I'm not sure how to handle the f(1) = 0 case. You can't take a log of a negative number.
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