Post a New Question


posted by .

a spherical balloon is inflated with gas at the rate of 500 cubic centimeters per minute. how fast is the radius of the balloon increasing at the instant the radius is 30 centimeters?

  • Calculus -

    The vloume increase rate is dV/dt = 500
    V = (4/3) pi R^3
    dV/dt = (12/3)pi R^2 dR/dt
    = 4 pi R^2 dR/dt

    You can use that equation to compute the dR/dt expansion rate for any value of R.

    Note that that dV/dt equals the instantaneous surface area times dR/dt.

  • Calculus -

    500=4 pi R^2 dR/dt
    500=11309.7336 dR/dt
    dR/dt = .0442cm/min

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question