4) A 1200 kg car is accelerating at 1.6 m/s2. If the coefficient of friction of friction is 0.15, what is the force applied to the car by the engine?
here do you use the equation kinetic friction= μk(normal force) and put in 1.6 m/s^2=.15(Fn) is this how you go about it?
To find the force applied to the car by the engine, you need to consider the net force acting on the car.
First, calculate the force of gravity acting on the car using the equation:
Weight = mass x acceleration due to gravity
Weight = 1200 kg x 9.8 m/s^2 (acceleration due to gravity)
Weight = 11,760 N
Next, calculate the normal force, which is the force exerted by the surface on the car in the vertical direction. In this case, the normal force is equal to the weight of the car since it is on a horizontal surface with no vertical acceleration or deceleration.
Normal Force = Weight of the car = 11,760 N
Now, calculate the frictional force using the equation:
Frictional Force = coefficient of friction x normal force
Frictional Force = 0.15 x 11,760 N
Frictional Force = 1,764 N
Since the car is accelerating, there must be an additional force applied by the engine to overcome the frictional force and accelerate the car. This additional force is equal to the net force acting on the car.
The net force can be calculated using Newton’s second law of motion:
Net Force = mass x acceleration
Net Force = 1200 kg x 1.6 m/s^2 (acceleration)
Net Force = 1920 N
Thus, the force applied to the car by the engine is equal to the net force which is 1920 N.