# precalc

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express the complex number in standard form(that is like a+bi)

1/2+i

2+i/2-i

• precalc -

rationalize the denominator. I will do one:

(2+i)/(2-i)= 2+i)(2+i)/(2-i)(2+i)=

(2+i)^2/(2-i^2)= (4+4i+i^2)/3
you can complete it.

• precalc -

so is that the final answer

• precalc -

os is the final answer 8i+i^3/3

• precalc -

(2+i)/(2-i)
=(2+i)(2+i)/((2+i)(2-i))
=(4+4i+i²)/(2²-i²)
=(4+4i-1)/(4-(-1))
=(3+4i)/5

You can proceed along the same lines for the first problem.

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