precalc

posted by .

express the complex number in standard form(that is like a+bi)


1/2+i



2+i/2-i

  • precalc -

    rationalize the denominator. I will do one:

    (2+i)/(2-i)= 2+i)(2+i)/(2-i)(2+i)=

    (2+i)^2/(2-i^2)= (4+4i+i^2)/3
    you can complete it.

  • precalc -

    so is that the final answer

  • precalc -

    os is the final answer 8i+i^3/3

  • precalc -

    (2+i)/(2-i)
    =(2+i)(2+i)/((2+i)(2-i))
    =(4+4i+i²)/(2²-i²)
    =(4+4i-1)/(4-(-1))
    =(3+4i)/5

    You can proceed along the same lines for the first problem.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Precalc

    Represent the complex number graphically and find the standard form of the number 5(cos 135* + isin 135*)
  2. precalc

    Suppose that z1=6-8i. Find: A. The Trig Form of the complex number z1, where your theta is in degrees. B. The Trig form of z1*z2, where z2=5[cos(60degrees)+isin(60degrees)] C. The Trig Form of (z1)^4
  3. trigonometry

    1)Solve and write in standard form: 4x^2-4x+21=0 2)Find the standard form of the complex number. 8(cos pi/2 + i sin pi/2) Thanks everyone!
  4. Precalc

    Write the complex number z = −6 in polar form
  5. Precalc

    Convert the complex number c=3cis 0.25 into rectangular form.
  6. Precalc

    Write the complex number z = 2 + 5i in polar form, rounding to the nearest hundredth if needed.
  7. math

    Express the complex number 8(cos30 degrees + i sin30 degrees)sin in complex in the form a+bi
  8. Mathematics

    Express the Complex Number -1-i in polar form. how is complex no expressed in polar form?
  9. Trig/Precalc

    The system of equations: |z-2-2i|=sqrt(23), |z-8-5i|=sqrt(38) has two solutions z_1 and z_2 in complex numbers. Find (z_1+z_2)/2. My first instinct on this problem was to square each equation given that the square of the magnitude …
  10. Precalc

    Why the polar form(2.83,45) is written a rectangular complex number like this: 2.83*cos45 + j*(2.83*sin45) I would like some explication please. Thanks!

More Similar Questions