physics
posted by Anonymous .
When a 4.48 kg mass is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.68 cm.
How much work must an external agent do to stretch the spring 3.96 cm from its unstretched position?

from the mass (remember mg is weight), find the spring constant.
Work=1/2 kx^2 
128.45
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