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A small bead of mass m is carried by a circular hoop of radius r which rotates about a fixed vertical axis. Show how one might determine the angular speed w of the hoop by observing the angle theta which locates the bead. Theta is measured to the right of the vertical axis. Neglect friction in your analysis, but assume that a small amount of friction exists to damp out any motion of the bead relative to the hoop once a constant motion has been established. Note any restrictions in your solution

ok so i keep getting that the angular speed is the square root of (g/rsin(theta)) but the answer is the square root of (g/rcos(theta)). Where am I going wrong?

  • physics -

    sorry the angle theta is measured below the radius to the vertical

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