Post a New Question

college physics

posted by .

A 190 g air-track glider is attached to a spring. The glider is pushed in 9.8 cm and released. A student with a stopwatch finds that 14 oscillations take 18.5 sec.
What is the spring constant?

  • college physics -

    frequency=1/2pi *sqrt(k/mass)
    and frequency is 1/period.

  • college physics -

    frequency= oscillations/second

    f=14osc/18.5sec=0.76Hz

    T= 1/f

    T= 2pi/w

    1/0.76Hz=2pi/w

    cross multiply

    w=2pi*0.76= 4.775 rad/s


    w=sqrt(k/m)

    square both sides

    w^2=k/m

    w^2 * m = k

    k = w^2 * m

    you have "w" and you have mass. Plug them in and find the spring constant. Don't forget to convert the mass from grams to kilograms.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question