A spherical tree ornament is to be painted in bright colors. If the ornament has a diameter of 4 cm,

how much paint is needed

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To calculate the amount of paint needed to cover the surface of a spherical tree ornament, we need to find the surface area of the ornament.

The formula for the surface area of a sphere is given by:

Surface Area = 4πr^2

where π is a constant (approximately equal to 3.14) and r is the radius of the sphere.

In this case, the diameter of the ornament is given as 4 cm. To find the radius, we need to divide the diameter by 2:

Radius = Diameter / 2 = 4 cm / 2 = 2 cm

Now we can substitute the radius value into the formula:

Surface Area = 4π(2 cm)^2

Surface Area = 4π(4 cm^2)

Surface Area = 16π cm^2

Since the question asks for the amount of paint needed, we can conclude that the ornament needs to be fully covered in paint. Therefore, the amount of paint needed is equal to the surface area of the ornament.

So, the amount of paint needed to paint the spherical tree ornament is 16π cm^2.

To find out how much paint is needed, we first need to calculate the surface area of the spherical tree ornament.

The surface area of a sphere can be calculated using the formula:

Surface Area = 4πr^2

Given that the diameter of the ornament is 4 cm, the radius can be calculated by dividing the diameter by 2:

Radius = Diameter / 2 = 4 cm / 2 = 2 cm

Now, substitute the value of the radius into the surface area formula:

Surface Area = 4π(2 cm)^2 = 4π(4 cm^2) = 16π cm^2

So, the surface area of the spherical tree ornament is 16π square centimeters.

To determine the amount of paint needed, we need to know the coverage rate of the paint. Let's assume that the paint covers 1 square centimeter with 1 ml of paint.

Therefore, the amount of paint needed can be calculated by multiplying the surface area of the ornament by the coverage rate:

Amount of Paint = Surface Area × Coverage Rate

Amount of Paint = 16π cm^2 × 1 ml/cm^2

Therefore, the amount of paint needed to paint the spherical tree ornament is 16π ml.