the sun's mass is 1.99*10^30 kg and it has a radius of 6.96*10^8 m.What is the Sun's gravitational field strength at its surface.
To calculate the Sun's gravitational field strength at its surface, we can use the formula:
g = G * (M / r^2)
Where:
g - Gravitational field strength
G - Gravitational constant (approximately 6.67430 × 10^-11 N m^2 kg^-2)
M - Mass of the Sun
r - Radius of the Sun
Now, let's substitute the values:
M = 1.99 * 10^30 kg
r = 6.96 * 10^8 m
g = (6.67430 × 10^-11 N m^2 kg^-2) * (1.99 * 10^30 kg) / (6.96 * 10^8 m)^2
First, let's calculate (1.99 * 10^30 kg) / (6.96 * 10^8 m)^2:
(1.99 * 10^30 kg) / (6.96 * 10^8 m)^2 = 4.019148-gessay10^11 kg m^-2
Now, multiply the answer by the gravitational constant (6.67430 × 10^-11 N m^2 kg^-2):
g = (6.67430 × 10^-11 N m^2 kg^-2) * 4.019148-gessay10^11 kg m^-2
g = 2.668-gessay10^-1 N kg^-1
Therefore, the Sun's gravitational field strength at its surface is approximately 2.668 × 10^-1 N kg^-1.