Physics
posted by rasuka_geo
In a ferris wheel, one person is at the top and another at the bttom. The ferris wheel rotates such that the magnitude of the tangetial velocity of each person is equal vtop=vbottom. Determine for the person at the bottom, the force the seat exerts on the person. Use a standard man mass of 70kg and the speed of the ferris wheel with 2.3 revolutions per minute and R=16.1m
I don't even know where to begin to attempt this problem!

bobpursley
force on the bottom: mg+ mv^2/r

Anonymous
is g gravity (9.81)?
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