Hey guys, been a long time since I have done this. Please show your work. Thanks a lot!
How many grams do 3.6 × 10^20 atoms of sodium weigh?
Answer in units of g
The molar mass of Na is approximately 23. You can look up the exact number.
23.0 grams Na will contain 6.022 x 10^23 atoms Na. So
3.6 x 10^20 atoms Na x (1 mole Na/6.02 x 10^23 Na atoms) x (23 g Na/1 mole Na) = ??
To calculate the weight of 3.6 × 10^20 atoms of sodium, we need to use the concept of molar mass and Avogadro's number.
1. Start by finding the molar mass of sodium (Na) on the periodic table. The molar mass of sodium is approximately 22.99 grams per mole (g/mol).
2. Next, we need to convert the given number of atoms to moles. To do this, divide the given number of atoms by Avogadro's number, which is approximately 6.022 × 10^23 atoms per mole.
(3.6 × 10^20 atoms of sodium) / (6.022 × 10^23 atoms per mole) = x moles
3. Now we can calculate the weight in grams by multiplying the number of moles by the molar mass of sodium.
x moles * (22.99 g/mol) = y grams
Substitute the value of x moles previously calculated to find the weight in grams.
4. Finally, calculate the weight of 3.6 × 10^20 atoms of sodium in grams.