mrs.ellis is 28 years older than her daughter. in 11 years she will be 3 times as old as her daughter. how old is each now?
chris - do your own homework.
at least try it first, show some work or where youre stuck on.
n=12 n+11=48
To solve this problem, let's break it down step by step.
Let's start by representing the age of Mrs. Ellis as "M" and the age of her daughter as "D".
We are given two pieces of information:
1. Mrs. Ellis is 28 years older than her daughter, so we can write the equation M = D + 28.
2. In 11 years, Mrs. Ellis will be 3 times as old as her daughter. This can be represented as (M + 11) = 3(D + 11).
Now we have a system of two equations with two variables:
Equation 1: M = D + 28
Equation 2: M + 11 = 3(D + 11)
We can solve this system of equations to find the values of M and D.
By substituting the first equation into the second equation, we get:
(D + 28) + 11 = 3(D + 11)
D + 39 = 3D + 33
39 - 33 = 3D - D
6 = 2D
D = 3
Now that we know the daughter's age, we can substitute D = 3 into the first equation to find Mrs. Ellis's age:
M = D + 28
M = 3 + 28
M = 31
So, the daughter is 3 years old and Mrs. Ellis is 31 years old.