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find the acceleration at time t=9s if the position (in cm) of a particle moving along a line is s(t)=6t^3-7t^2-9t+2 at time t.

  • Calculus -

    V(t) = dS/dt = 18t^2 - 14t -9

    Acceleration = dV/dt = 36t-14

    Plug the value of "t" in the above and that's the answer

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