Mathematics
posted by Anonymous .
The surface area of a piece of gold is directly proportional to the square of its weight. By what ratio should the weight be adjusted so as to double the surface area.

surface area= k w^2
w=sqrt (area/k)
double surface area.
w'=w sqrt2 
Thanks.I had a similar question in my recent exam. I followed a similar procedure...Made a silly error though at the end,forgot to square root..I ended up with w^2'=2w^2.