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The surface area of a piece of gold is directly proportional to the square of its weight. By what ratio should the weight be adjusted so as to double the surface area.

  • Mathematics -

    surface area= k w^2

    w=sqrt (area/k)
    double surface area.
    w'=w sqrt2

  • Mathematics -

    Thanks.I had a similar question in my recent exam. I followed a similar procedure...Made a silly error though at the end,forgot to square root..I ended up with w^2'=2w^2.

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