Caluclus
posted by Z32 .
[Mean Value Theorem]
f(x)=3x^3  4x^2  2x 3 on the closed interval [0,8].
Find the smallest value of c that satisfies the conclusion of the Mean Value Theorem for this function defined on the given interval.
I got 8  sqrt(5696) / 18 = 3.748436059 but it's not right.
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