A sample of the primary standard, Potassium hydrogen phthalate, weighing 0.3589g requires 14.96mL of NaOH solution for neutralization. calculate the molarity of the NaOH solution.
The molar mass of KHC8H4O4 is 204.22g
Use the above value to convert 0.3589g of "KHP" to moles.
The mole ratio of NaOH to KHP is 1/1 (same number of moles).
Molarity = moles / 0.01496 L = __________M
To calculate the molarity of the NaOH solution, we need to use the equation:
Molarity (M) = moles of solute / volume of solution (in liters)
First, we need to find the moles of Potassium hydrogen phthalate (KHP). The molar mass of KHP is 204.23 g/mol.
moles of KHP = mass of KHP / molar mass of KHP
moles of KHP = 0.3589 g / 204.23 g/mol
Next, we have to use the balanced chemical equation of the reaction between KHP and NaOH to determine the moles of NaOH.
The balanced equation is:
KHP + NaOH -> KNaP + H2O
From the balanced equation, we can see that the stoichiometric ratio between KHP and NaOH is 1:1. This means that 1 mole of KHP reacts with 1 mole of NaOH.
Therefore, moles of NaOH = moles of KHP.
Now, we can calculate the molarity of the NaOH solution:
Molarity (M) = moles of NaOH / volume of NaOH solution (in liters)
Since the volume given is in milliliters, we need to convert it to liters:
volume of NaOH solution = 14.96 mL = 14.96 mL * (1 L / 1000 mL) = 0.01496 L
Now we can substitute the values into the equation to calculate the molarity:
Molarity (M) = moles of NaOH / volume of NaOH solution
Molarity (M) = moles of KHP / volume of NaOH solution
Therefore, the molarity of the NaOH solution is equal to the moles of KHP divided by the volume of the NaOH solution in liters.