Calculus
posted by sh .
Differentiate the following function:
y= [x+1]/√x
I tried
y=[x+1]/x^(1/2)
y' =1/2√x
y'=2√x
Thanks in advance.

OH MY!
my first line after the quotient rule is
dy/dx = (√x  (1/2)x(1/2)(x+1))/x
which reduces to (x+1)/(2x^(3/2)) 
What did you do to get the first line?

As I said, I used the quotient rule.
Judging by the type of question you are differentiating, you must know that.
alternate way,
change your question to
y = (x+1)(x^(1/2)) and use the product rule.
same result of course. 
Oh, I haven't learnt the quotient rule, only the power rule, thanks.

ok then try this
y = (x+1)/√x
= x/√x + 1/√x
= x^(1/2) + x^(1/2)
so dy/dx = (1/2)x(1/2)  (1/2)x^(3/2)
= (1/2)x^(3/2)[x  1}
= (x1)/(2x^(3/2))
Just noticed that in my intial reply I had x+1 instead of x1 in the numerator.
This last result is the correct one. 
The back of the textbook just left it as y'= (1/2)x(1/2)  (1/2)x^(3/2)
Thanks! :)
Respond to this Question
Similar Questions

Algebra
How would i complete these problems? 1. (√6mn)^5 2. ^3√16x  ^3√2x^4 3.^4√x • ^3√2x 4. ^3√72x^8 5. √63a^5b • √27a^6b^4 and are these problems correct? 
Math
Find an equation of the line that bisects the obtuse angles formed by the lines with equations 3xy=1 and x+y=2. a. (3√2 +√10)x(√10 + √2)y2√10+√2=0 b. (3√2  √10)x+(√10  √2)y+2√10+√2=0 … 
maths
I will be thankfull to you if you help me to solve the below problem: 6√x11/3√x=2√x+1/√x+6 I tried to solve the above problem like this: (6√x11)(√x+6)=(3√x)(2√x+1) 6√x(√x+6)11(√x+6)=(3√x)(2√x)+(3√x)(1) … 
Algebra
Simplify the expressions and solve the equations 1. 2√3  √12 My answer: 2√3  2√3 = 0 2. √(5p + 5)^2 = √(6p + )^2 I got the answer p = 4 3. √(28) + √(63) + √(175) This one seems … 
Algebra Work Check
1. 5√6 * 1/6√216 5/6 * √1296 5/6 * √144 * √9 = 30 2. 9√28a^2 * 1/3√63a 3√1764a^3 3√49a^2 * √36a 3*7a*6√a = 126a√a 
Algebra 2 Answer Check
Simplify by rationalizing each denominator. 1. 2/√3 A: 2√3 / 3 2. 18/√6 A: 3√6 Add or subtract. 3. 4√3  9√3 A: 5√3 4. √8  15√2 A: 13√2 5. √45 + √20 A: 5√5 … 
8th grade algebra
Can you check my answers? 1. 3√20/√4 = 3√(5)(4)/2 = 3(2)√5/2 = 3√5 2. 4√15/√9 = 4√15/3 3. √12/√16 = √4(3)/4 = 2√3/4 = √3/2 4. √10/√5 = √2 
Algebra
1. Simplify the expression: 4√18+5√32 A.45√2 B.32√2 C.116√2 D.9√50 2. Simplify the expression: 7√53√80 A.5√5 B.4√75 C.5 D.4√75 3. Simplify the expression: √21(√3+√14) … 
Algebra
1.Simplify the radical expression. √5+6√√5 A.5√5 B.7√10 C.7√5 D.5√10 2.Simplify the radical expression. 2√6+3√96 A.14√6 B.14√96 C.5√96 D.50√6 3.Simplify … 
Algebra  Check My Work
For Question 18 Simplify the Radical Expression ***  My Answer 1.√45 3√5*** 2.√180x^2 6x√5*** 3.√150x^3 k^4 5xk^2√6x*** 4.√21y * 5√49y 35y√21*** 5.(The square root sign applies …