A train accelerates from rest at a constant rate of 10 m/s^2. How fast is it going after 5 s?
vfinal= vo+ at
does vo stand for the initial velocity and would that be 0m/s
correct.
so 0m/s + (10)(5) equals the final velocity and the answer would be 50 m/s? thanks for your help
yes.
To find the speed of the train after 5 seconds, we can use the equation of motion:
v = u + at
Where:
v is the final velocity,
u is the initial velocity (0 m/s since the train starts from rest),
a is the acceleration (10 m/s^2),
t is the time (5 seconds).
Plugging in the given values into the equation:
v = 0 + (10 m/s^2) * (5 s)
= 0 + 50 m/s
= 50 m/s
Therefore, the train is going at a speed of 50 m/s after 5 seconds.