Please help me, i don't know how to approach this question!
All ammonium salts on heating with sodium hydroxide produce ammonia gas. From which ammonium salt can the greatest mass of ammonia be obtained?
a)0.5 mol of (NH4)3PO4
b)0.5 mol of (NH4)2SO4
c)1 mol of NH4Cl
d)1 mol of NH4NO3
How do i calculate? The correct answer is A.
Please help, thanks!
a) if you have three ammonium ions per molecule, then .5 moles ofthe salt will produce 1.5 moles ammonia.
i also in need to helpingness
also this queston is dumb.. it tells you finding the mass not the number of moles and it wants ammonia..not ammonium ..IT DOEN'T MAKE..SENSE!
To determine which ammonium salt can produce the greatest mass of ammonia gas, we need to compare the molar masses of the salts. Ammonia gas (NH3) is produced by the decomposition of ammonium salts according to the following reaction:
(NH4)X → XNH3 + H2O
The molar masses of the given ammonium salts are:
a) (NH4)3PO4 → molar mass = 149.09 g/mol
b) (NH4)2SO4 → molar mass = 132.14 g/mol
c) NH4Cl → molar mass = 53.49 g/mol
d) NH4NO3 → molar mass = 80.05 g/mol
To calculate the mass of ammonia gas produced, we need to compare the number of moles of ammonia gas that can be formed from each ammonium salt.
a) (NH4)3PO4:
Number of moles of ammonia = 0.5 mol × 3 = 1.5 mol
Mass of ammonia = number of moles × molar mass = 1.5 mol × 17.03 g/mol = 25.55 g
b) (NH4)2SO4:
Number of moles of ammonia = 0.5 mol × 2 = 1 mol
Mass of ammonia = number of moles × molar mass = 1 mol × 17.03 g/mol = 17.03 g
c) NH4Cl:
Number of moles of ammonia = 1 mol × 1 = 1 mol
Mass of ammonia = number of moles × molar mass = 1 mol × 17.03 g/mol = 17.03 g
d) NH4NO3:
Number of moles of ammonia = 1 mol × 1 = 1 mol
Mass of ammonia = number of moles × molar mass = 1 mol × 17.03 g/mol = 17.03 g
Therefore, the greatest mass of ammonia gas can be obtained from option a) 0.5 mol of (NH4)3PO4, which gives 25.55 g of ammonia.