6 lollies and 3 icecreams cost £8.52
3 icecreams and 6 drinks cost £9.24
What would the cost of 1 lolly, 1 icecream and 1 drink be?
add the two equations:
6lol+6cream+6drinks=8.52+9.24
divide both sides of the equation by 6
Thank you
To solve this problem, we can set up a system of equations. Let's assign the following variables:
- Let's assume the cost of 1 lolly is L.
- Let's assume the cost of 1 ice cream is I.
- Let's assume the cost of 1 drink is D.
From the given information, we can create two equations:
Equation 1: 6L + 3I = £8.52 (6 lollies and 3 ice creams cost £8.52)
Equation 2: 3I + 6D = £9.24 (3 ice creams and 6 drinks cost £9.24)
To find the cost of 1 lolly, 1 ice cream, and 1 drink, we need to find the values of L, I, and D.
To solve this system of equations, we can use the method of substitution or elimination. We will use the method of substitution.
From Equation 1, we can isolate L in terms of I:
6L = £8.52 - 3I
L = (£8.52 - 3I)/6
Now substitute this expression for L into Equation 2:
3I + 6D = £9.24
3I + 6D = £9.24
Replace L with (£8.52 - 3I)/6 in the above equation:
3I + 6D = £9.24
3I + 6D = £9.24
Now, we can solve this equation for the values of I and D.
3I + 6D = £9.24
Let's multiply the equation by 2 to eliminate the coefficient of I:
6I + 12D = £18.48
Next, subtract this equation from Equation 1:
6I + 12D = £18.48
- (3I + 6D = £9.24)
-------------------
3I + 6D = £9.24
Now we have:
0I + 0D = £9.24 - £18.48
0D = -£9.24
Since the cost cannot be negative, this implies that there is no unique solution to this system of equations.
Hence, we cannot determine the exact cost of 1 lolly, 1 ice cream, and 1 drink. The given information is inconsistent or incomplete.
Please check if there are any missing values or if the given information is accurate.