A cylindrical can of cleaner holds 1 L of liquid. What is its height if the diameter of the base is 12 cm? Round your answer to the nearest tenth of a cm.
1 liter is 1000cm^3
1000cm^3=areabase*height
area base is PI(diameter^2)/4
solve for h.
I am so lost?
3.1415*12^2/4=113.094
is that right?
To find the height of the cylindrical can, we need to use the formula for the volume of a cylinder.
The formula for the volume of a cylinder is given by: V = πr^2h, where V is the volume, r is the radius of the base, and h is the height.
We are given that the can holds 1 L of liquid, which is equivalent to 1000 cm^3 (since 1 L = 1000 cm^3). We are also given that the diameter of the base is 12 cm, so the radius (r) can be found by dividing the diameter by 2: r = 12 cm / 2 = 6 cm.
Substituting these values into the formula, we have: 1000 cm^3 = π(6 cm)^2h.
To solve for h, we can rearrange the formula as follows: h = (1000 cm^3) / (π(6 cm)^2).
Calculating this expression, we get the value of h ≈ 8.5 cm (rounded to the nearest tenth of a cm).
Hence, the height of the cylindrical can is approximately 8.5 cm.