Physics
posted by Anonymous .
you swing the pail in a vertical circle of radius 0.900m.What minimum speed must you give the pail at the highest point of the circle if no water is to spill from it?

well, centripetal force must be greater than weight
mg<=mv^2/r
v>=sqrt(g*r)
check that. 
i don't know where to go from there

v is the minimum speed.

Consider the following equation in the ydirection.
Fy=T+Fg=ma
Or in this case...
T+Fg=(mv^2)/R
Tension equals to 0 because when the pail of water is at the highest point, tension is nonexistent.
Therefore...
mg=(mv^2)/R
Cancel out mass
g=(v^2)/R
(Rg)^(1/2)=v
Plug in values.
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